Optimal. Leaf size=61 \[ \frac {2 (b B-2 a C) \tan ^{-1}\left (\frac {\sqrt {a-b} \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a+b}}\right )}{d \sqrt {a-b} \sqrt {a+b}}+C x \]
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Rubi [A] time = 0.12, antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 48, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {24, 2735, 2659, 205} \[ \frac {2 (b B-2 a C) \tan ^{-1}\left (\frac {\sqrt {a-b} \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a+b}}\right )}{d \sqrt {a-b} \sqrt {a+b}}+C x \]
Antiderivative was successfully verified.
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Rule 24
Rule 205
Rule 2659
Rule 2735
Rubi steps
\begin {align*} \int \frac {a b B-a^2 C+b^2 B \cos (c+d x)+b^2 C \cos ^2(c+d x)}{(a+b \cos (c+d x))^2} \, dx &=\frac {\int \frac {b^2 (b B-a C)+b^3 C \cos (c+d x)}{a+b \cos (c+d x)} \, dx}{b^2}\\ &=C x+(b B-2 a C) \int \frac {1}{a+b \cos (c+d x)} \, dx\\ &=C x+\frac {(2 (b B-2 a C)) \operatorname {Subst}\left (\int \frac {1}{a+b+(a-b) x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{d}\\ &=C x+\frac {2 (b B-2 a C) \tan ^{-1}\left (\frac {\sqrt {a-b} \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a+b}}\right )}{\sqrt {a-b} \sqrt {a+b} d}\\ \end {align*}
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Mathematica [A] time = 0.13, size = 68, normalized size = 1.11 \[ \frac {2 (2 a C-b B) \tanh ^{-1}\left (\frac {(a-b) \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {b^2-a^2}}\right )}{d \sqrt {b^2-a^2}}+\frac {C (c+d x)}{d} \]
Antiderivative was successfully verified.
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fricas [A] time = 1.07, size = 240, normalized size = 3.93 \[ \left [\frac {2 \, {\left (C a^{2} - C b^{2}\right )} d x + {\left (2 \, C a - B b\right )} \sqrt {-a^{2} + b^{2}} \log \left (\frac {2 \, a b \cos \left (d x + c\right ) + {\left (2 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} + 2 \, \sqrt {-a^{2} + b^{2}} {\left (a \cos \left (d x + c\right ) + b\right )} \sin \left (d x + c\right ) - a^{2} + 2 \, b^{2}}{b^{2} \cos \left (d x + c\right )^{2} + 2 \, a b \cos \left (d x + c\right ) + a^{2}}\right )}{2 \, {\left (a^{2} - b^{2}\right )} d}, \frac {{\left (C a^{2} - C b^{2}\right )} d x - {\left (2 \, C a - B b\right )} \sqrt {a^{2} - b^{2}} \arctan \left (-\frac {a \cos \left (d x + c\right ) + b}{\sqrt {a^{2} - b^{2}} \sin \left (d x + c\right )}\right )}{{\left (a^{2} - b^{2}\right )} d}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 1.37, size = 318, normalized size = 5.21 \[ \frac {\frac {{\left (\sqrt {a^{2} - b^{2}} B b^{2} {\left | a - b \right |} - \sqrt {a^{2} - b^{2}} C {\left (a + b\right )} {\left | a - b \right |} {\left | b \right |} + \sqrt {a^{2} - b^{2}} B b {\left | a - b \right |} {\left | b \right |} - \sqrt {a^{2} - b^{2}} {\left (3 \, a b - b^{2}\right )} C {\left | a - b \right |}\right )} {\left (\pi \left \lfloor \frac {d x + c}{2 \, \pi } + \frac {1}{2} \right \rfloor + \arctan \left (\frac {2 \, \sqrt {\frac {1}{2}} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{\sqrt {\frac {2 \, a + \sqrt {-4 \, {\left (a + b\right )} {\left (a - b\right )} + 4 \, a^{2}}}{a - b}}}\right )\right )}}{{\left (a^{2} - 2 \, a b + b^{2}\right )} b^{2} + {\left (a^{3} - 2 \, a^{2} b + a b^{2}\right )} {\left | b \right |}} - \frac {{\left (3 \, C a b - B b^{2} - C b^{2} - C a {\left | b \right |} + B b {\left | b \right |} - C b {\left | b \right |}\right )} {\left (\pi \left \lfloor \frac {d x + c}{2 \, \pi } + \frac {1}{2} \right \rfloor + \arctan \left (\frac {2 \, \sqrt {\frac {1}{2}} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{\sqrt {\frac {2 \, a - \sqrt {-4 \, {\left (a + b\right )} {\left (a - b\right )} + 4 \, a^{2}}}{a - b}}}\right )\right )}}{b^{2} - a {\left | b \right |}}}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.15, size = 108, normalized size = 1.77 \[ \frac {2 \arctan \left (\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (a -b \right )}{\sqrt {\left (a -b \right ) \left (a +b \right )}}\right ) B b}{d \sqrt {\left (a -b \right ) \left (a +b \right )}}-\frac {4 \arctan \left (\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (a -b \right )}{\sqrt {\left (a -b \right ) \left (a +b \right )}}\right ) a C}{d \sqrt {\left (a -b \right ) \left (a +b \right )}}+\frac {2 C \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 2.50, size = 248, normalized size = 4.07 \[ \frac {2\,C\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,B^2\,b^2-4\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,B\,C\,a\,b+3\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,C^2\,a^2+\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,C^2\,b^2}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (B^2\,b^2-4\,B\,C\,a\,b+3\,C^2\,a^2+C^2\,b^2\right )}\right )}{d}-\frac {2\,B\,b\,\mathrm {atanh}\left (\frac {a\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )-b\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\sqrt {b^2-a^2}}\right )}{d\,\sqrt {b^2-a^2}}+\frac {4\,C\,a\,\mathrm {atanh}\left (\frac {a\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )-b\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\sqrt {b^2-a^2}}\right )}{d\,\sqrt {b^2-a^2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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